Question
If a refrigerator contains 12 cans such that 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that atleast 1 blue can and 1 red can remains in the refrigerator?
Answers
Possible ways of keeping atleast 1 blue and 1 red ball are drawing cans like (6,2) (5,3) (4,4)
(6,2) ⇒⇒7C6×5C27C6×5C2 ⇒⇒ 710 = 70
(5,3) ⇒⇒7C5×5C37C5×5C3 ⇒⇒ 21 x 10 = 210
(4,4) ⇒⇒7C4×5C47C4×5C4 ⇒⇒ 35 x 5 = 175
70 + 210 + 175 = 455.   Your Comment




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