Question
int DIM(int array[]) {
return sizeof(array)/sizeof(int );
}
main(){
int arr[10];
printf(“The dimension of the array is %d”, DIM(arr));
}
Answers
1
Explanation:
Arrays cannot be passed to functions as arguments and only the pointers can be passed. So the argument is equivalent to int * array (this is one of the very few places where [] and * usage are equivalent). The return statement becomes, sizeof(int *)/ sizeof(int) that happens to be equal in this case.   Your Comment




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