Question
So what is meant by the "equivalence of pointers and arrays" in C?
Answers
An lvalue of type array-of-T which appears in an expression decays into a pointer to its first element; the type of the resultant pointer is pointer-to-T. So for an array a and pointer p, you can say "p = a;" and then p[3] and a[3] will access the same element.   Your Comment




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