Question
I'm getting the same mess with destructors: calling a virtual on my this object from my base class's destructor ends up ignoring the override in the derived class; what's going on?
Answers
C++ is protecting you from yourself. What you are trying to do is very dangerous, and if the compiler did what you wanted, you'd be in worse shape.

For rationale of why C++ needs to protect you from that danger, read FAQ 3]. The situation during a destructor is analogous to that during the constructor. In particular, within the {body} of Base::~Base(), an object that was originally of type Derived has already been demoted (devolved, if you will) to an object of type Base. If you call a virtual function that has been overridden in class Derived, the call will resolve to Base::virt(), not to the override Derived::virt(). Same goes for using typeid on the this object: the this object really has been demoted to type Base; it is no longer an object of type Derived.

Read FAQ 3] for more insight on this matter.   Your Comment




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