Question
Here the sum of the series is 4+8+12+16+….. =612. Find how many terms are there in the series?
Answers
This is an A.P. in which a=4, d=4 and Sn=612
Then, n/2[2a+(n1)d]=612 => n/2[2*4+(n1)*4]=612
=> 4n/2(n+1)=612
=> n(n+1)=306
=> n^2+n306=0
=> n^2+18n17n306=0
=> n(n+18)17(n+18)=0
=> (n+18)(n17)=0
=> n=17.
Number of terms=17.   Your Comment




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